1.

For the reaction 2A+B rarr product, doubling the initial concentrations of both the reactants increases the rate by a factor of 8 and doubling the concentration of B above double the rate. This rate-law for the reaction is

Answer»

`r=k[A][B]^(2)`
`r=k[A][B]`
`r=k[A]^(2)[B]^(2)`
`r=k[A]^(2)[B]`

Solution : Since doubling the concentration of B doubles the rate therefore the order of REACTION w.r.t. [B] is one and since on doubling the conc. of A and B rate INCREASES 8 times, therefore order of reaction w.r.t. A will be 2.
`i.e.""rprop[A]^(2)[B]`
or`r=k[A]^(2)[B]`


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