1.

For the reaction, 2A+Bto2C,/_\G^0=2kJ. Mol^(-1) at 500K. Calculate the value of equilibrium constant for the reaction, A+1/2BtoC, at the same temperature.

Answer»

SOLUTION :`/_\G^0=/_\G^0(PCl_3)+/_\G^0(Cl_2)-/_\G^0(PCl_5)`
`=(-68.42+0+77.6)kcal=+9.18kcal=+3.84xx10^4J`
`:.-2.303RT" "logK=3.84xx10^4`
or `logK=-6.73" ":.K=1.86xx10^(-7)`


Discussion

No Comment Found

Related InterviewSolutions