1.

For the reaction 2H_(2)+O_(2)rarr2H_(2)O, DeltaH=-571.Bond energy of H-H = 435, O=O = 498, then calculate the average bond energy of O-H bond using the above data

Answer»

484
`- 484`
271
`- 271`

Solution :`2H_(2)+O_(2)rarr2H_(2)O, DeltaH=-571`
`DeltaH_("REATION")=2xxB.E(H_(2))+B.E(O_(2))-2xxB.E.(H_(2)O)`
`THEREFORE -571=(2xx435)+498-2xxB.E. (H_(2)O)`
`or, 2xxB.E(H_(2)O)=870+498+571`
`B.E(H_(2)O)=(1939)/(2)=(969.5)`
`B.E(O-H)=(969.5)/(2)=484.75`.


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