For the reaction `2H_(2)+O_(2)rarr2H_(2)O, DeltaH=-571`. Bond energy of H-H = 435, O=O = 498, then calculate the average bond energy of O-H bond using the above dataA. 484B. `- 484`C. 271D. `- 271`

For the reaction `2H_(2)+O_(2)rarr2H_(2)O, DeltaH=-571`. Bond energy o

1.	For the reaction `2H_(2)+O_(2)rarr2H_(2)O, DeltaH=-571`. Bond energy of H-H = 435, O=O = 498, then calculate the average bond energy of O-H bond using the above dataA. 484B. `- 484`C. 271D. `- 271`
Answer» Correct Answer - A `2H_(2)+O_(2)rarr2H_(2)O, DeltaH=-571` `DeltaH_("reation")=2xxB.E(H_(2))+B.E(O_(2))-2xxB.E.(H_(2)O)` `therefore -571=(2xx435)+498-2xxB.E. (H_(2)O)` `or, 2xxB.E(H_(2)O)=870+498+571` `B.E(H_(2)O)=(1939)/(2)=(969.5)` `B.E(O-H)=(969.5)/(2)=484.75`.