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For the reaction: 2N_(2)O_(5)(g) to 4NO_(2)(g)+O_(2)(g), the rate of formation of NO_(2)(g) is 2.8xx10^(-3)Ms^(-1). Calculate the rate of disappearance of N_(2)O_(5)(g). |
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Answer» Solution :`2N_(2)O_(5)(g) to 4NO_(2)(g)+O_(2)(g)` Rate of formation of `NO_(2)(g) =2.8xx10^(-3)M s^(-1)` Rate of disappearance of `N_(2)O_(5)(g)=2.8xx10^(-3)XX(2)/(4)=1.4xx10^(-3)MS^(-1)` |
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