1.

For the reaction 2NH_3 to N_2 +3H_2, if -(d[NH_3])/(dt)=k_1[NH_3], (d[N_2])/(dt)=k_2[NH_3], (d[H_2])/(dt)=k_3[NH_3] then the relation between k_1,k_2 and k_3 is

Answer»

`k_1= k_2=k_3`
`k_1=3 k_2=2k_3`
`1.5k_1= 3k_2 =k_3`
`2k_1=k_2=3k_3`

SOLUTION :`2 NH_3 to N_2 + 3H_2`
`RATE = - 1/2(d[NH_3])/(DT)= (d[N_2])/(dt) = 1/3(d[H_2])/(dt)`
`1.5k_1=3k_2= k_3`


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