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For the reaction 2NH_3 to N_2 +3H_2, if -(d[NH_3])/(dt)=k_1[NH_3], (d[N_2])/(dt)=k_2[NH_3], (d[H_2])/(dt)=k_3[NH_3] then the relation between k_1,k_2 and k_3 is |
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Answer» `k_1= k_2=k_3` `RATE = - 1/2(d[NH_3])/(DT)= (d[N_2])/(dt) = 1/3(d[H_2])/(dt)` `1.5k_1=3k_2= k_3` |
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