1.

For the reaction, 2NH_3rarrN_2+3H_2, if (-d[NH_3])/(dt)=k_1[NH_3], (d[N_2])/(dt)=k_2[NH_3], (d[H_2])/(dt)= k_3[NH_3]then the relation between k_1,k_2 and k_3 is .....

Answer»

`k_1 = k_2 = k_3`
`k_1 = 3 k_2=2k_3`
`1.5k_1=3k_2=k_3`
`2k_1=k_2=3k_3`

SOLUTION :`(-1/2)(d[NH_3])/(DT)=(d[N_2])/(dt)=(1/3)(d[H_2])/((dt))`
`(1/2)k_1[NH_3]=k_2[NH_3]=(1/3)k_3[NH_3]`
`(3/2)k_1=3k_2=k_3`
`1.5k_1=3k_2=k_3`


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