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For the reaction : 2NO_(2)+F_(2) to 2NO_(2)F, the experimental rate law is given as : Rate =K[NO_(2)][F_(2)], propose the mechanism. |
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Answer» SOLUTION :The Rate `=K[NO_(2)][F_(2)]` implies that SLOW step of reaction uses only one molecule of each reactant to FORM product, thus we can write the mechanism as : `ul{:(NO_(2)+F_(2)toNO_(2)F+F,,("slow")),(NO_(2)+FtoNO_(2)F,,("FAST")):}` Overall reaction, `2NO_(2)+F_(2)to2NO_(2)F` |
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