1.

For the reaction :2NO_(2)(g)hArr 2NO(g)+O_(2)(g) K_(c )=1.8xx10^(-6) at 185^(@)C, the value of K_(c ) for the reactionNO+(1)/(2)O_(2)=NO_(2)is:

Answer»

`0.9xx10^(6)`
`7.5xx10^(2)`
`1.95xx10^(-3)`
`1.95xx10^(3)`

Solution :`2NO_(2)(g)HARR 2NO(g)+O_(2)(g)K_(C )=1.8xx10^(-6)`
`2NO+O_(2)hArr 2NO_(2)K.=(1)/(1.8xx10^(-6))`
`NO+(1)/(2)O_(2)hArr NO_(2)`
`K..=SQRT((1)/(1.8xx10^(-6)))=7.45xx10^(2)`


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