1.

For the reaction 2NO_(2(g))hArr2NO_((g))+O_(2(g)) K_(c)=1.8xx10^(-6)at 185^(@)C. At 185^(@)C, the value of K_(c) for reaction NO_((g))+1/2O_(2(g))hArrNO_(2(g)) is

Answer»

`0.9xx10^(6)`
`7.5xx10^(2)`
`1.95xx10^(-3)`
`1.95xx10^(3)`

SOLUTION :Reaction is REVERSED and halved.
`K=sqrt(1//18xx10^(-6))=7.5xx10^(2)`


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