1.

For the reaction , 2NO_(2) rarr 2NO+ O_(2) rate is expressed as :

Answer»

`-(1)/(2)(d[NO_(2)])/(dt)=-(1)/(2)(d[NO])/(dt)= (d[O_(2)])/(dt)`
`-(2D[NO_(2)])/(dt)= (2d[NO])/(dt)=(d[O_(2)])/(dt)`
`-(1)/(2)(d[NO_(2)])/(dt)=(1)/(2)(d[NO])/(dt)=(d[O_(2]])/(dt)`
`-(d[NO_(2)])/(dt)=d([NO])/(dt)=(2d[O_2])/(dt)`

Answer :C


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