For the reaction, 2X + 3Y → 4Z, reaction may be represented as :(a) Rate = \(-\frac{1}{2}\)\(\frac{d[X]}{dt}\) = \(\frac{1}{3}\)\(\frac{d[Y]}{dt}\) = \(\frac{1}{4}\)\(\frac{d[Z]}{dt}\)(b) Rate = \(-\frac{1}{2}\)\(\frac{d[X]}{dt}\) = \(-\frac{1}{3}\)\(\frac{d[Y]}{dt}\) = \(\frac{1}{4}\)\(\frac{d[Z]}{dt}\)(c) Rate = \(\frac{1}{2}\)\(\frac{d[X]}{dt}\) = \(\frac{1}{3}\)\(\frac{d[Y]}{dt}\) = \(\frac{1}{4}\)\(\frac{d[Z]}{dt}\)(d) Rate = \(\frac{1}{2}\)\(\frac{d[X]}{dt}\) = \(-\frac{1}{3}\)\(\frac{d[Y]}{dt}\) = \(-\frac{1}{4}\)\(\frac{d[Z]}{dt}\)

For the reaction, 2X + 3Y → 4Z, reaction may be represented as :(a)

1.	For the reaction, 2X + 3Y → 4Z, reaction may be represented as :(a) Rate = \(-\frac{1}{2}\)\(\frac{d[X]}{dt}\) = \(\frac{1}{3}\)\(\frac{d[Y]}{dt}\) = \(\frac{1}{4}\)\(\frac{d[Z]}{dt}\)(b) Rate = \(-\frac{1}{2}\)\(\frac{d[X]}{dt}\) = \(-\frac{1}{3}\)\(\frac{d[Y]}{dt}\) = \(\frac{1}{4}\)\(\frac{d[Z]}{dt}\)(c) Rate = \(\frac{1}{2}\)\(\frac{d[X]}{dt}\) = \(\frac{1}{3}\)\(\frac{d[Y]}{dt}\) = \(\frac{1}{4}\)\(\frac{d[Z]}{dt}\)(d) Rate = \(\frac{1}{2}\)\(\frac{d[X]}{dt}\) = \(-\frac{1}{3}\)\(\frac{d[Y]}{dt}\) = \(-\frac{1}{4}\)\(\frac{d[Z]}{dt}\)
Answer» Option : (b) Rate = \(-\frac{1}{2}\)\(\frac{d[X]}{dt}\) = \(-\frac{1}{3}\)\(\frac{d[Y]}{dt}\) = \(\frac{1}{4}\)\(\frac{d[Z]}{dt}\)

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