1.

For the reaction 2x+yrarrL find the rate law from the following data. {:([x](min),[y](min),Rate(Ms^(-1))),(0.2,0.02,0.15),(0.4,0.02,0.30),(0.4,0.08,1.20):}

Answer»

SOLUTION :Rate `=k[X]^m[y]^m`
`0.15=k[0.2]^N[0.02]^m""...(1)`
`0.30=k[0.4]^n[0.02]^m""...(2)`
`1.20=k[0.4]^n[0.08]^m""...(3)`
`{:("Dividing Eq(3) by Eq(2) we get","Dividing Eq(2) by Eq(1) we get"),(1.2/0.3=(k[0.4]^n[0.08]^m)/(k[0.4]^n[0.02]^m),0.30/0.15=(k[0.4]^n[0.02]^m)/(k[0.2]^n[0.02]^m)),(4=(([0.08])/([0.02]))^m,2=(([0.4])/([0.2]))^n),(thereforem=1,thereforen=1):}`
Rate `=k[x]^1[y]^1`
`0.15=k[0.2]^1[0.02]^1`
`(0.15)/([0.2]^1[0.02]^1)=k`
`k=37.5"MOL ^(-1) Ls^(-1)`


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