For the reaction `A_(2)(g) + 2B_(2)hArr2C_(2)(g)` the partial pressure of `A_(2)` and `B_(2)` at equilibrium are `0.80` atm and `0.40` atm respectively.The pressure of the system is `2.80` atm. The equilibrium constant `K_(p)` will beA. (A) `20`B. (B) `5.0`C. (C) `0.02`D. (D) `0.02`

For the reaction `A_(2)(g) + 2B_(2)hArr2C_(2)(g)` the partial pressure

1.	For the reaction `A_(2)(g) + 2B_(2)hArr2C_(2)(g)` the partial pressure of `A_(2)` and `B_(2)` at equilibrium are `0.80` atm and `0.40` atm respectively.The pressure of the system is `2.80` atm. The equilibrium constant `K_(p)` will beA. (A) `20`B. (B) `5.0`C. (C) `0.02`D. (D) `0.02`
Answer» Correct Answer - A `A_(2)(g)+2B_(2)(g)hArr2C_(2)(g)` `P_(A_(2)=0.80atm. P_(B_(2)=0.4` atm. Total pressure of the system`=2.8` atm. `thereforeP_(C_(2)=2.8-0.8-0.4=1.6` `Kp=(P_(C_(2)^(2))/(P_(A_(2)+P_(B_(2)^(3))))=((1.6)^(2))/(0.8+(0.4))^(2)=20`

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For the reaction `A_(2)(g) + 2B_(2)hArr2C_(2)(g)` the partial pressure of `A_(2)` and `B_(2)` at equilibrium are `0.80` atm and `0.40` atm respectively.The pressure of the system is `2.80` atm. The equilibrium constant `K_(p)` will beA. (A) `20`B. (B) `5.0`C. (C) `0.02`D. (D) `0.02`

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