For the reaction `A+2BhArrC, `the expression for equlibrium constant isA. `([A][B]^(2))/([C])`B. `([A][B])/([C])`C. `([C])/([C][B]^(2))`D. `([C])/(2[B][A])`

For the reaction `A+2BhArrC, `the expression for equlibrium constant i

1.	For the reaction `A+2BhArrC, `the expression for equlibrium constant isA. `([A][B]^(2))/([C])`B. `([A][B])/([C])`C. `([C])/([C][B]^(2))`D. `([C])/(2[B][A])`
Answer» Correct Answer - C

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For the reaction `A+2BhArrC, `the expression for equlibrium constant isA. `([A][B]^(2))/([C])`B. `([A][B])/([C])`C. `([C])/([C][B]^(2))`D. `([C])/(2[B][A])`

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