1.

For the reaction A  B, the rate law expression is-(d[A])/(dt) =k [A]^(1//2). If initial concentration of [A] is [A]_(0), then

Answer»

The integerated rate expression is `K=(2)/(t) (A_(0)^(1//2)-A^(1//2))`
The graph of `SQRT(A)` Vs t will be

The half life period `t_(1//2)=(K)/(2[A]_(0)^(1//2))`
The TIME taken for 75% completion of reaction `t_(3//4) =(sqrt[A]_(0))/(k)`

Answer :A::B::D


Discussion

No Comment Found

Related InterviewSolutions