1.

For the reaction A+B to C+D, doubling the concentration of both the reactants increases the reaction rate by 8 times and doubling the concentration of only B simply doubles the reaction rate. The rate law is given as

Answer»

`r=k[A]^(1//2)[B]^(1//2)`
`r=k[A][B]^(2)`
`r=k[A]^(2)[B]`
`r=k[A][B]`

Solution :`(i) r = k a^(alpha) b^(BETA)`
(ii) `8 r = k ( 2a)^(alpha) ( 2B)^(beta)`
`(iii) 2R = ka^(alpha)(2b)^(beta)`
Eqn. (ii) Eqn. (iii) GIVES `(8)/(2) = 2^(alpha)`
or `2^(alpha) = 4 = 2^(2) or alpha = 2.` ,
Eqn. (iii) Eqn. (i) gives `2 = 2^(beta) or beta = 1`, Hence rate ` = k[A]^(2) [B].`


Discussion

No Comment Found

Related InterviewSolutions