1.

For the reaction, A+BhArr C+D, the initial concentration of A and B are equal, but the equilibrium concentration of C istwice that of equlibrium concentration of A. The equlibrium constant is

Answer»


Solution :`{:(A,+,B,hArr,C,+,D),(a,,a,,0,,0),((a-x),,(a-x),,x,,x):}`
GIVEN `x=2(a-x)or x=(2a)/(3)`
`K_(c)=(x^(2))/((a-x)^(2))=((2a//3)^(2))/((a-2a//3)^(2))=4`


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