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For the reaction: `aA + bB rarr cC+dD` Rate `= (dx)/(dt) = (-1)/(a)(d[A])/(dt) = (-1)/(b)(d[B])/(dt) = (1)/( c)(d[C])/(dt) = (1)/(d)(d[D])/(dt)` In the following reaction, `xA rarr yB` `log.[-(d[A])/(dt)] = log.[(d[B])/(dt)] + 0.3` where negative isgn indicates rate of disappearance of the reactant. Thus, `x:y` is:A. `1:2`B. `2:1`C. `3:1`D. `3:10` |
Answer» Correct Answer - B `xA rarr yB` `(-d[A])/(x dt) = (1)/(y) (d[B])/(dt)` `log.((-d[A])/(dt)) = log.(d[B])/(dt) + log.(x)/(y)` `:. log.((x)/(y)) = 0.3` `:. (x)/(y) = 2` or `x:y = 2:1` |
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