1.

For the reaction at 298 K : CO(g) + (1)/(2) O_(2)(g) rarr CO_(2)(g), Delta H^(@) = -282.8 kJ Standard entropies (in JK^(-1) mol^(-1)) : CO_(2)(g) = 213.6 CO(g) = 197.6 and O_(2)(g) = 205.0 Delta_(r) G^(@) for the reaction (kJ mol^(-1))

Answer»

`-306.02`
`-257.81`
306.02
`-157.03`

SOLUTION :`Delta S^(@) = S^(@) (CO_(2)) - [S^(@)(CO) + (1)/(2) S^(@)(O_(2))]`
`= 213.6 - [197.6 + (1)/(2)(205.0)]`
`= - 86.5 JK^(-1) MOL^(-1)`
`Delta G^(@) = -282.8 xx 10^(3) - 298(-86.5)`
`= -257.023 KJ mol^(-1)`


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