1.

For the reaction at 298K, A_((g))+B_((g))rarrC_((g)) DeltaE=-5 cal and DeltaS =-10cal K^(-1)

Answer»

`DeltaG=+2612 CAL`
`DeltaG=-2612 cal`
`DeltaG=+261.2 cal`
`DeltaG=2379 cal`

SOLUTION :`DeltaH=DeltaE+DeltanRT=-5-1xx2.0xx298=-601`
`DeltaG=DeltaH-TDeltaS=-601-298xx(-10)=2379 cal`.


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