1.

For the reaction at 800KN_(2)(g)+3H_(2)(g)hArr 2NH_(3)(g)the ratio of K_(p)and K_(c ) is:(R = 0.082 L atm mol^(-1)K^(-1))

Answer»

<P>`2.3xx10^(-4)`
`3.2xx10^(-6)`
`2.3xx10^(4)`
`3.2xx10^(6)`

Solution :`K_(p)=K_(c )(RT)^(DELTA N)`
or `K_(p)=K_(c )(RT)^(-2)`
`=(K_(c ))/((0.082xx800)^(2))`
or `(K_(p))/(K_(c ))=2.32xx10^(-4)`


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