1.

For the reaction AtoB,DeltaH=+23kJ//mol and BtoC,DeltaH=-18kJ//mol, the decreasing order of enthalpy of A,B,C follows the order

Answer»

A,B,C
B,C,A
C,B,A
C,A,B

Solution :`A to B,DeltaH=+24" kJ "mol^(-1)`
`H_(B)-H_(A)=+24`. . ..(i)
`B to C, DeltaH=18" kJ "mol^(-1)`
`H_(C)-H_(B)=-18`. . (ii)
`H_(B)-H_(C)=+18`. . (iii)
`H_(C)-H_(A)=6`(from (i) and (ii))
`H_(B) GT H_(C) gt H_(A)`.


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