1.

For the reaction Aunderset(k_(2)"sec"^(-1))overset(K_(1)"sec"^(-1))hArr B following graph is given, k_(1) =4 xx 10^(-@)"sec"^(-1). Which is/are correct statement (s) (In 2=0.7 , In 8/7 =0.14)

Answer»

EQUILIBRIUM constant is 4.0
Time taken for the completion fo 50% fo equilibrium conc. Of B is 14 sec.
Time taken for the completion of 10% of INITIAL conc. Of A is 2.8 sec.
Rate constant of BACKWARD reaction is `10^(-2)"sec"^(-1)`

Answer :A::B::C::D


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