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For the reaction, CaCO_(3)(s) iff CaO(s)+CO_(2)(g)partial pressure of CO_(2) at 1000 K is 0.003 atm. DeltaG^(@)=27.2 kcal. Calculate the value of DelaG |
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Answer» 12.6 kcal `K_(p)=P_(CO_(2))=0.003 atm` `DeltaG=DeltaG^(@)+2.303 RT LOG K_(p)` `=27.2+2.303xx2xx1000xxlog 0.003` `=15.6 kcal (R=2 cal mol^(-1)K^(-1))`. |
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