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For the reaction : CaCOs (s) CaO(s) + CO2 (g), Kp 1.16 atm at 800°C. If 20g of CaCO3 were keptin a 10 litre vessel at 800°C, the amount of CaCO3 remained at equilibrium is(1) 34%(2) 64%(3) 46%(4) none |
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Answer» molecular mass of CaCO3=100mole of CaCO3=20/100 =.2 molemolarit of CaCO3=.2/10 =.02LtCaCO3 ------------->CaO +CO2.02 0 0.02-x x xKp =pCO21.16=x*.082*1073x=.013unreacted=.007percentage=34% |
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