1.

For the reaction Cl_(2)+2I^(-)toI_(2)+2CI^(-), the initial concentration of I^(-) was 0.20 mol "lit"^(-1) and the concentration after 20 min was 0.18 mol "lit"^(-1). If the rate of formation of I_(2) in mol "lit"^(-1) "min"^(-1) is x xx 10^(-4) then the value of x is

Answer»


SOLUTION :`(r_(I^(-)))/2=(r_(I_(2)))/1,r_(I_(2))=0.001/2=5xx10^(-4),r_(I^(-))=(0.20-0.18)/20=0.02/20=0.001`


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