1.

For the reaction :CO(g)+1//2O_(2)(g)hArr CO_(2)(g)the partial pressures are :p(O_(2))=0.24atm, p(CO)=0.4 atm and p(CO)=0.04 atm.The equilibrium constant K_(p)is :

Answer»

<P>`0.3`
`3.0`
`9.0`
`0.03`

SOLUTION :`K_(p)=((p CO_(2)))/(p(CO)xx [p(O_(2))]^(1//2))`
`=(0.24)/(0.4xx(0.04)^(1//2))=3.0`


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