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For the reaction [Cu(NH_(3))_(4)]^(2+) + H_(2) O [ Cu ( NH_(3))_(3) H_(2) O ] ^(2+ ) + NH_(3) Net rate is ((dx)/(dt)) = 2.0 xx 10^(-4) s^(-1) [[ Cu (NH_(3))_(4) ]^(2+) ] - 3.0 xx 10^(5) L mol^(-1) s^(_1) [[ Cu ( NH_(3))_(3) H_(2) O ] (NH_(3))] Ratio of rate constant of the forward and backward reactions is |
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Answer» `0.66 XX 10^(-9) mol L^(-1)` |
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