1.

For the reaction:[Cu(NH_(3))_(4)]^(2+)+H_(2)OhArr[Cu(NH_(3))_(3)H_(2)O]^(2+)+NH_(3) The net rate of reaction at any time is given by: rate =2.0xx10^(-4)[[Cu(NH_(3))_(4)]^(2+)][H_(2)O]-3.0xx10^(5)[[Cu(NH_(3))_(3)H_(2)O]^(2+)][NH_(3)] The correct statement is (are)

Answer»

Rate constannt for forward reaction `=2XX10^(-4)`
Rate constant for BACKWARD reaction `=3xx10^(5)`
Equilibrium constant for the reaction `=6.6xx10^(-10)`
At equilibrium, NET rate =0

Solution :`K_(f)=2xx10^(-4),K_(b)=3xx10^(5),`
`K_(c)=(K_(f))/(K_(b))=(2xx10^(-4))/(3xx10^(-5))=0.666xx10^(-9)=6.66xx10^(-10)`


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