1.

For the reaction Fe_(2)O_(3)+3CO rarr 2Fe+3CO_(2), the volume of carbon monoxide required to reduce one mole of ferric oxide is

Answer»

`67.2 dm^(2)`
`11.2 dm^(2)`
`22.4 dm^(3)`
`44.8 dm^(3)`

Solution :`{:(Fe_(2)O_(3),+,3CO,rarr,2Fe,+,3CO_(2)),("1 vol.",,"3 vol.",,"2 vol.",,"3 vol."),("1 mol.",,"3 mol.",,"2 mol.",,"3 mol."):}`
`( :' "vol% = mol%")`
One gram mol of any GAS occupies 22.4 litre at NTP. 1 mol of `Fe_(2)O_(3)` requires 3 mol of `CO` for its reduction i.e., 1 mol of `Fe_(2)O_(3)` requires `3xx22.4` litre or `67.2 dm^(3) CO` to GET itself REDUCED.


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