1.

For the reaction Fe_(2)O_(3)+3COto2Fe+3CO_(2),the volume of carbon monoxide required to reduceone mole of ferricoxide is

Answer»

`67.2dm^(3)`
`11.2dm^(3)`
`22.4dm^(3)`
`44.8dm^(3)`

SOLUTION :`{:(Fe_(2)O_(3)+3COto2Fe+3CO_(2),),(1vol." " 3vol " " 2vol . " " 3vol.,),(1mol " " 3 mol. " " 2 mol.""3MOL,):}`
`(becausevol%=mol%)`.
One GRAM mol of any gas occupies 22.4 litre at NTP. 1 mol of `Fe_(2)O_(3)` REQUIRES 3 mol of CO for its REDUCTION i.e., 1 mol of `Fe_(2)O_(3)`
requires `3xx22.4` litre or 67.2 `dm^(3)` CO to get itself reduced .


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