1.

For the reaction, following data is given AtoB:K_(1)=10^(15) exp ((-2000)/T)""CtoD,K_(2)=10^(14) exp ((-1000)/T) The temperature at whilch K_(1)=K_(2) is

Answer»

1000 K
2000 K
868.4 K
434.22 K

Solution :`K_(1)=K_(2),10^(15).e^(((-2000)/T))=10^(14).e^(((-1000)/T)),10.e^(((-2000)/T))=e^(((-1000)/T)),10=(e^((1000/T)))/(e^(((-200)/T))),10=e^(((-1000)/T))XXE^(((-2000)/T))`
`10=e^((-1000-2000)/T),10=e^((1000/T)),10=1000/T,2.303log_(10)^(10)=1000/T,T=1000/2.303=434.2K`


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