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For the reaction given below the value of standard Gibbs free energy of formation at 298 K are given. What is the nature of the reaction? `I_(2)+H_(2)Srarr2HI+S` `DeltaS_(f)^(@)(HI)="1.8 kJ mol"^(-1), DeltaG_(f)^(@)(H_(2)S)="33.8 kJ mol"^(-1)`A. Non-spontaneous in forward direction.B. Spontaneous in forward direction.C. Spontaneous in backward direction.D. Non-spontaneous in both forward and backward directions. |
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Answer» Correct Answer - B `I_(2)+H_(2)S rarr 2HI +S` `DeltaG^(@)=SigmaG_(f"(Products)")^(@)-SigmaG_(f"(Reactants)")^(@)` `DeltaG^(@)=(2xx1.8+0)-(0+33.8)=-"30.2 kJ"` Hence, reaction is spontaneous in forward direction. |
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