1.

For the reaction H_(2)(g)+(1)/(2)O_(2)(g)rarrH_(2)O(l),DeltaH=-285.8kJ mol^(-1)DeltaS=-0.163 kJ mol^(-1) K^(-1). What is the value of free energy change at 27^(@)C for the reaction

Answer»

`-236.9 KJ mol^(-1)`
`-281.4 kJ mol^(-1)`
`-334.7 kJ mol^(-1)`
`+334.7 kJ mol^(-1)`

Solution :`DELTAG=DeltaH-TDeltaS, T=27+273=300 K`
`DeltaG=(-285.8)-(300)(-0.163)=-236.9 kJ mol^(-1)`


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