InterviewSolution
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InterviewSolution
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For the reaction, `H_(2)(g)+CO_(2)(g) hArr CO(g)+H_(2)O(g)`, if the initial concentration of `[H_(2)]=[CO_(2)]` and x mol `L^(1)` of `H_(2)` is consumed at equilibrium, the correct expression of `K_(p)` is:A. `x^(2)/((1-x)^(2))`B. `((1+x)^(2))/((1-x)^(2))`C. `(1+x^(2))/((2+x)^(2))`D. `x^(2)/(1+x^(2))` |
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Answer» Correct Answer - A::B::C `{:(,H_(2)(g),+,CO_(2)(g),hArr,CO(g),+,H_(2)O(g)),(t=0,x,,x,,0,,0),(t=t_("Eq"),1-x,,1-x,,x,,x):}` `:. K=([CO][H_(2)O])/([H_(2)][CO_(2)])=x^(2)/((1-x)^(2))` |
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