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For the reaction `H_(2)(g) + I_(2)(g)hArr2HI(g)` at 721 K the value of equilibrium constant `(K_(c))` is 50. When the equilibrium concentration of both is `0.5` M, the value of `K_(p)` under the same condtions will beA. `0.002`B. `0.2`C. `50.0`D. `50//RT` |
Answer» Correct Answer - C For the reaction `H_(2) + I_(2)hArr 2HI` `Delta n = 0` So `K_(p) = K_(c) :. 50.0` |
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