1.

For the reaction H_(2)+I_(2)hArr2Hl, the equilibrium concentration of H_(2),I_(2)and HI are 8.0. 3.0 and 28.0 mol per litre respectively, the equlibrium constant of the reaction is

Answer»

`30.66`
`32.66`
`34.66`
`36.66`

SOLUTION :`K_(c)=([HI]^(2))/([H_(2)][I_(2)])=((28)^(2))/(8xx3)=32.66`


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