For the reaction is equilibrium : `2NOBr_((g))hArr2NO_((g))+Br_(2(g))` If `P_(Br_(2))` is `(P)/(9)` at equilibrium and `P` is total pressure, prove that `(K_(p))/(P)` is equal to `(1)/(81)`.

For the reaction is equilibrium : `2NOBr_((g))hArr2NO_((g))+Br_(2(g))`

1.	For the reaction is equilibrium : `2NOBr_((g))hArr2NO_((g))+Br_(2(g))` If `P_(Br_(2))` is `(P)/(9)` at equilibrium and `P` is total pressure, prove that `(K_(p))/(P)` is equal to `(1)/(81)`.
Answer» `{:(,2NOBr_((g)),hArr,2NO_((g)),+,Br_(2(g))),("P at equilibrium",p-(3P)/(9)=(6P)/(9),,(2P)/(9),,(P)/(9)):}` `:. P_(T)=(6P)/(9)+(2P)/(9)+(P)/(9)=P` `K_(p)=(((2P)/(9))^(2)((P)/(9)))/(((6P)/9)^(2))=(P)/(81)`

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For the reaction is equilibrium : `2NOBr_((g))hArr2NO_((g))+Br_(2(g))` If `P_(Br_(2))` is `(P)/(9)` at equilibrium and `P` is total pressure, prove that `(K_(p))/(P)` is equal to `(1)/(81)`.

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