For the reaction is equilibrium : `2NOBr_((g))hArr2NO_((g))+Br_(2(g))` If `P_(Br_(2))` is `(P)/(9)` at equilibrium and `P` is total pressure, prove that `(K_(p))/(P)` is equal to `(1)/(81)`.A. `1//9`B. `1//81`C. `1//27`D. `1//3`

For the reaction is equilibrium : `2NOBr_((g))hArr2NO_((g))+Br_(2(g))`

1.	For the reaction is equilibrium : `2NOBr_((g))hArr2NO_((g))+Br_(2(g))` If `P_(Br_(2))` is `(P)/(9)` at equilibrium and `P` is total pressure, prove that `(K_(p))/(P)` is equal to `(1)/(81)`.A. `1//9`B. `1//81`C. `1//27`D. `1//3`
Answer» `K_(p)=((P_(NO))^(2)(P_(Br)))/((P_(NOBr))^(2))`, `underset(P-(3P)/(9)=(6P)/(9))(2NOBr)hArrunderset((2P)/(9))(2NO)+underset((P)/(9))(Br_(2))` Total pressure `=(6P)/(9)+(2P)/(9)+(P)/(9)=P` `K_(P)=(((2P)/(9))^(2)xx((P)/(9)))/(((6P)/(9))^(2))` `K_(p)=(P)/(81)`

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For the reaction is equilibrium : `2NOBr_((g))hArr2NO_((g))+Br_(2(g))` If `P_(Br_(2))` is `(P)/(9)` at equilibrium and `P` is total pressure, prove that `(K_(p))/(P)` is equal to `(1)/(81)`.A. `1//9`B. `1//81`C. `1//27`D. `1//3`

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