InterviewSolution
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InterviewSolution
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For the reaction `M^(x+)+MnO_(4)^(ө)rarrMO_(3)^(ө)+Mn^(2+)+(1//2)O_(2)` if `1 "mol of" MnO_(4)^(ө)` oxidises `1.67 "mol of" M^(x+) "to" MO_(3)^(ө)`, then the value of `x` in the reaction isA. 5B. 3C. 2D. 1 |
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Answer» Correct Answer - C 1 mole of `Mn^(+7)O_4^(-)` changes of `Mn^(+2)` by gaining of 5 electrons. i.e., 5 moles of electrons are lost by 1.67 moles of `M^(x+)` `therefore` 1 mole of `M^(x+)` will lose electrons `=5/1.67=3.01` Since `M^(x+)` changes to `MO_3^(-)` where oxidation state of M= +5 . |
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