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For the reaction, `N_(2)+3H_(2)hArr2NH_(3)`, in a vessel equal moles of `N_(2)` and `H_(2)` are mixed to attain equilibrium. At equilibrium:A. `[N_(2)]=[H_(2)]`B. `[N_(2)]gt[H_(2)]`C. `[N_(2)]lt[H_(2)]`D. `[H_(2)]gt[NH_(3)]` |
Answer» `{:(N_(2),+,3H_(2),hArr,2NH_(3)),(a,,a,,0),((a-x),,(a-3x),,):}` ` :. (a-x) gt (a-3x)` |
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