1.

For the reaction N_2+ 3H_2 to 2NH_3 the rate of change of concentration for hydrogen is -0.3 xx 10^(-4) Ms^(-1). The rate of change of concentration of ammonia is

Answer»

`-0.2 xx 10^(-4)`
`0.2 xx 10^(-4)`
`0.1 xx 10^(-4)`
`0.3 xx 10^(-4)`

SOLUTION :`(d[H_2])/(DT)=-0.3xx 10^(-4)Ms^(-1)`
`"Rate"=-1/3(d[H_2])/(dt)=+1/2(d[NH_3])/(dt)`
Hence `(d[NH_3])/(dt)=-2/3(d[H_2])/(dt)`
`=-2/3 xx (-0.3xx 10^(-4))`
`=0.2xx 10^(-4)Ms^(-1)`


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