1.

For the reaction N_(2)+3H_(2)to2NH_(3) , the rate (d[NH_(3)])/(dt)=2xx10^(-4)Ms^(-1).Therfore the rate -(d[N_(2)])/(dt) is given

Answer»

`10^(-4)M"sec"^(-1)`
`10^(4)M"sec^(-1)`
`10^(-2)M"sec"^(-1)`
`4xx10^(-4)M"sec"^(-1)`

Solution :`(r_(N_(2)))/1=(r_(H_(2)))/3=(r_(NH_(3)))/2,r_(N_(2))=(2xx10^(-4))/2=10^(-4)`


Discussion

No Comment Found

Related InterviewSolutions