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For the reaction `N_(2)(g) + 3H_(2)(g) hArr 2NH_(3)(g), DeltaH=?`A. `DeltaE+2RT`B. `DeltaE-2RT`C. `DeltaE+RT`D. `DeltaE-RT` |
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Answer» Correct Answer - D `Delta H = Delta E + Delta n_(g) RT` `Delta n_(g) = 2 - u = -2` So, `Delta H = Delta E + (-2RT)` `= Delta E - 2RT` |
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