For the reaction N_(2)(g)+3H_(2)(g)hArr2NH_(3)(g) at 298K, enthalpy an – InterviewSolution

1.	For the reaction N_(2)(g)+3H_(2)(g)hArr2NH_(3)(g) at 298K, enthalpy and entropy changes are -92.4 kJ and -198.2 JK^(-1) respectively. Calculate the equilibrium constant of the reaction (R=8.314JK^(-1)mol^(-1)).
Answer» SOLUTION :`DELTAG=DeltaH-TDeltaS`. CALCULATE `DeltaG`.

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