1.

For the reaction, N_(2(g))+3H_(2(g))hArr2NH_(3(g))at 400K, K_(p)=41 Find the vlaue of K_(p) for the following reaction 1/2N_(2(g))+3/2H_(2(g))hArrNH_(3(g))

Answer»

`6.4`
`0.02`
50
`4.6`

Solution :`K_(p)=([p_(NH_(3))])/([P_(N_(2))][P_(H_(2))]^(3))=41`
`impliesP_(NH_(3))=SQRT(K_(p)[P_(N_(2))][P_(H_(2))]^(3))""...(i)`
`K'_(p)=([P_(NH_(3))])/([P_(N_(2))]^(1//2)[P_(H_(2))]^(3//2))""...(II)`
Putting (i) in (ii), we get
`K'_(p)=sqrt(K_(p)[P_(N_(2))][P_(H_(2))]^(3))=sqrt(41)=6.4.`


Discussion

No Comment Found

Related InterviewSolutions