1.

For the reaction N_(2(g)) + O_(2(g)) hArr 2NO_((g))the value of K, at 800^(@)C is 0.1. When the equilibrium concentrations of both the reactants is 0.5 mol, what is the value of K_(p) at the same temperature?

Answer»

<P>0.5
0.1
0.01
0.025

Solution :`N_(2(g))+O_(2(g))hArr2NO(g)`
`K_(c)=0.1,K_(p)=K_(c)(RT)^(/_\N)`
`/_\n=0,K_(p)=K-(c)=0.1`


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