1.

For the reaction, N_(2)O_(4(g))hArr2NO_(2(g)) DeltaU=2.1kCal,DeltaS=20" Cal "K^(-1) at 300K, then DeltaG is:-

Answer»

`+9.3` KCAL
`-9.3` kCal
`-3.3` kCal
`+3.3` kCal

Solution :`DeltaH=DeltaU+Deltan_(G)RT`
`=2.1+(1xx2xx300)/(1000)`
`=2.1+0.6`
`=2.7` kCal
`DeltaG=DeltaH-TDeltaS`
`=2.7-(300xx20)/(1000)`
`=2.7-6`
`=-3.3` kCal


Discussion

No Comment Found

Related InterviewSolutions