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For the reaction N_(2)O_(5)to2NO_(2)+1/2O_(2), Given (-d[N_(2)O_(5)])/(dt)=K_(1)[N_(2)O_(5)], (d[NO_(2)])/(dt)=K_(2)[N_(2)O_(5)] and (d[O_(2)])/(dt)=K_(3)[N_(2)O_(4)]. The relation in between K_(1),K_(2) and K_(3) is |
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Answer» `k_(1)=2k_(2)=3k_(3)` |
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